Penny Blood: Serial Sensation and Working-Class Entertainment — page 155: what you’re looking at

Machine-transcribed from the original scan — historical spelling and the odd misread are preserved.

138 DISTURBED TRACT. (cH. x. whence, subtracting, p {(a+2) 2— aA} =o (y,9,- — ¥,9;)- If then we assume the vertical to pass through the centre of gravity of the volumes y, and ¥,, the second side will vanish, and we have (c +2) a =aA. This shows that the centre of gravity of the mass 2 before its removal, and of 2+2z after their deposition in their new position, is in the same vertical with the centre of gravity of y, and y,. Hence we can find the position of the centre of gravity of these latter volumes but not the position of the volumes | themselves. It shows that the centre of gravity of y, and y, travels eastward at exactly the same rate as that of x before denudation and # + z after deposition. We may next compare the rate at which the centre of gravity of the whole tract travels, relatively to the vertical through the centre of gravity of y,, y,. For if M be the mass of the whole tract before the transference and deposition of sediment, and consequently M+<z afterwards, M, M’ the dis- tances of their centres of gravity from an assumed vertical, then we have at first M.M=2A+B.B; and afterwards (M+2)M' =(c2+2)0+B.B. But if we measure from the vertical which passes through the centre of gravity of y,, ¥,, we know that A =(a@+2)@; . (M+2z) M’ —MM=0. If z=0, then M’=M. So that by the transference of x alone, the centre of gravity of the whole mass remains at a constant distance from the vertical through that of ¥,, y,, not depending upon the amount of x. , commiclsoolkks (CO) ee eel OC a ee