Penny Blood: Serial Sensation and Working-Class Entertainment — page 133: what you’re looking at

Machine-transcribed from the original scan — historical spelling and the odd misread are preserved.

116 DISTURBED TRACT. (cu. x. Let us consider the former condition first. Then, using the same letters, but dashed, to refer to the effective surface of the fluid, as we have used for the upper surface of the crust, p. 46, and supposing that a volume 2%(d) of water covers the hollows of the disturbed region, since the weight of the fluid displaced is gc A'EB’DFC, or go {kl(1 +e) —3%(a’) +%(b)}, and the weight of the mass supported is gpkl (1 +e) + gu (d), we have for the first condition of equilibrium, o {kl (1 +e) —Z (a) + &(0’)} = pki (1 +e) +p (d). . S(@)- 20) =P a te—-£ 3a. But we also have the geometrical relation, x(a’) — (a) + (6) — 2 (0) = rectangle AA’B’B, = BB' x l, = “—P 1-81, oe oC therefore subtracting, > (a) — 3(6) = -—f ile + © (81-3 (d)). Since 8/ is the volume of water which would have covered the tract if there had been no elevations, and 3(d) is the volume of the water which rests upon it after elevation, we may in general take 61 — %(d) to be the volume of rock elevated so as to replace water below the water level. If there be no com- pression, or e= 0, then 2%(d) is 8; so also if o=p, for in that case the crust would float in the fluid without any part emerged, so that %(d) would be 62. Thus either of the conditions e=0, or o =p, should reduce each side of our equescn to zero, as it will evidently do. commiclsoolkks (CO)