Penny Blood: Serial Sensation and Working-Class Entertainment — page 120: what you’re looking at

Machine-transcribed from the original scan — historical spelling and the odd misread are preserved.

—_ CH, Ix.] CRUST NOT FLEXIBLE. 103 If the two values of y’ be made equal, they will give the points of contrary flexure. If we put = =1,this will give the maximum and minimum ordinates. Now we know that one of these 1s —f. Hence we may find D; , Dot + p(k-8)f Substituting this value we get for the said ordinates, —f— (k-8) + © (k—8), and their difference, Pk — 2 - (k —8). We have from equation (2), by making r infinite, since ¢ is not infinite, at a point of contrary flexure, p = gpk cos 8, or — go (y +f) +9p6 = gpk cos 8. Substituting the corresponding value of cos @ in the general equation, we get yaty/p+28 ba) / for the depth of the point of contrary flexure. The negative sign must be taken. The radii of curvature are, at an anticlinal, k—6’ and at a synclinal, kf p =T_5 +2 o k. To determine the constant f we must discuss the conditions at an anticlinal, Consider any element ds of the curve, and let the horizontal and vertical components which act upon it from beyond at one extremity of it be GONG oOo SS (CO)